(8-n)^2=2(24-n^2)

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Solution for (8-n)^2=2(24-n^2) equation: 



(8-n)^2=2(24-n^2)

We move all terms to the left:

(8-n)^2-(2(24-n^2))=0

We add all the numbers together, and all the variables

-(2(24-n^2))+(-1n+8)^2=0



We calculate terms in parentheses: -(2(24-n^2)), so:

2(24-n^2)

We multiply parentheses

-2n^2+48

Back to the equation:

-(-2n^2+48)



We get rid of parentheses

2n^2+(-1n+8)^2-48=0

We move all terms containing n to the left, all other terms to the right

2n^2+(-1n+8)^2=48

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